At zero acceleration a particle moves along a straight line. What is the velocity of a particle at the position of
x = t4 -20t2 + 42 ?
a. + 48.68 m/sec
b. - 48.68 m/sec
c. + 42 m/sec
d. - 42 m/sec
ANSWER: - 48.68 m/sec
x = t4 -20t2 + 42 ?
a. + 48.68 m/sec
b. - 48.68 m/sec
c. + 42 m/sec
d. - 42 m/sec
ANSWER: - 48.68 m/sec
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