a. 200 kHz
b. 2 kHz
c. 4.4 kHz
d. None of these
ANSWER: 4.4 kHz
Explanation:
Given data :
Frequency Deviation = Δf = 10 x ( 2π 200) rad
Deviation ratio = D = [10 x ( 2π 200)] / [( 2π 200)]
Therefore, D = 10
Bandwidth of Frequency Modulated Signal is given by,
B = 2 (D + 1) fm
= 2 (10 +1 ) x 200
= 2 (11) x 200
= 22 x 200
= 4400
= 4.4 kHz
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